1. What percent is:-
i) 12 of 80
ii) 25 rupees of 4 rupees
iii) 300g of 2 kg
2. A school team won 6 games this year against 4 games won last year. What is the percent increase
3. The price of a shirt decreased from 80 to 60, find the percentage of decrease in the price of the shirt
4. My mother says, in her childhood petrol was 1 per litre. It is 65 per litre today.By what percentage has the prices of petrol gone up?
5. Rate of basmati rice last year was 40 a kg. This year they are costly by 20%. What is the price this year?
6. 300 students took an exam. 28% failed. Calculate the number of students whopassed the exam
7. Out of 15000 voters in a constituency, 60% voted. Find the number of voters who did not vote.
8. 20% of length of a flagpole is painted green, 45% is painted yellow and there maining red. If the length of the pole is 18 m, what length of it is painted red?
9. Chalk contains 10% calcium, 3% carbon, 12% oxygen and the remaining sand
Find the amount of carbon and calcium (in grams) in 2½ kg of chalk. Also find the amount of sand (in kg)
Answers
Answer:
1. (i) 12 of 80 = 12/80×100 = 15%.
(ii) 25 rupees of 4 rupees = 25/4×100 = 625%
(iii) 300g of 2kg = (1kg = 1000g) = 300/2000×100
= 15%.
2. Increase = 6-4 = 2
Increase % = 2/4×100
= 50%.
3. Decrease = 80-60 = 20
Decrease % = 20/80×100
= 25%.
4. Increase = 65-1 = 64
Increase % = 64/1×100
= 6400%.
5. Increase of price this year = 40×20/100 = 8
Price of this year = 40+8 = 48.
6. Total students = 300
Failed % students = 28%
Passed % students = 100% - 28% = 72%
No. of students has passed = 72/100×300 = 216.
7. Total voters = 15000
Voters voted % = 60%
Voters did not voted = 100%-60% = 40%
No. of voters did not voted = 40/100×15000
= 6000.
8. The length of the pole = 18 m
% of painted by green colour = 20%
% of painted by yellow colour = 45%
% of painted by red colour = 100% - 45% - 20%
= 35%
Length of pole coloured by red = 35/100×18
= 6.3 %
9. Weigh of chalk = 2 1/2 kg = 2500 g
% of carbon = 3%
No. of amount in carbon = 3/100×2500 = 75 g
% of calcium = 10%
No. of amount in calcium = 10/100×2500 = 250 g
% of oxygen = 12%
% of sand = 100% - 12% - 10% - 3% = 75%
No. of amount in sand = 75/100×2500 = 1875 g
I hope this is helpful to you..........
Answer:
1 (I)=15 (ii)625(iii) 15 is the answer