Question

1. What percent is:-
i) 12 of 80
ii) 25 rupees of 4 rupees
iii) 300g of 2 kg
2. A school team won 6 games this year against 4 games won last year. What is the percent increase

3. The price of a shirt decreased from 80 to 60, find the percentage of decrease in the price of the shirt

4. My mother says, in her childhood petrol was 1 per litre. It is 65 per litre today.By what percentage has the prices of petrol gone up?

5. Rate of basmati rice last year was 40 a kg. This year they are costly by 20%. What is the price this year?

6. 300 students took an exam. 28% failed. Calculate the number of students whopassed the exam

7. Out of 15000 voters in a constituency, 60% voted. Find the number of voters who did not vote.

8. 20% of length of a flagpole is painted green, 45% is painted yellow and there maining red. If the length of the pole is 18 m, what length of it is painted red?

9. Chalk contains 10% calcium, 3% carbon, 12% oxygen and the remaining sand
Find the amount of carbon and calcium (in grams) in 2½ kg of chalk. Also find the amount of sand (in kg)

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Answer 1

Answer:

1. (i) 12 of 80 = 12/80×100 = 15%.

(ii) 25 rupees of 4 rupees = 25/4×100 = 625%

(iii) 300g of 2kg = (1kg = 1000g) = 300/2000×100

= 15%.

2. Increase = 6-4 = 2

Increase % = 2/4×100

= 50%.

3. Decrease = 80-60 = 20

Decrease % = 20/80×100

= 25%.

4. Increase = 65-1 = 64

Increase % = 64/1×100

= 6400%.

5. Increase of price this year = 40×20/100 = 8

Price of this year = 40+8 = 48.

6. Total students = 300

Failed % students = 28%

Passed % students = 100% - 28% = 72%

No. of students has passed = 72/100×300 = 216.

7. Total voters = 15000

Voters voted % = 60%

Voters did not voted = 100%-60% = 40%

No. of voters did not voted = 40/100×15000

= 6000.

8. The length of the pole = 18 m

% of painted by green colour = 20%

% of painted by yellow colour = 45%

% of painted by red colour = 100% - 45% - 20%

= 35%

Length of pole coloured by red = 35/100×18

= 6.3 %

9. Weigh of chalk = 2 1/2 kg = 2500 g

% of carbon = 3%

No. of amount in carbon = 3/100×2500 = 75 g

% of calcium = 10%

No. of amount in calcium = 10/100×2500 = 250 g

% of oxygen = 12%

% of sand = 100% - 12% - 10% - 3% = 75%

No. of amount in sand = 75/100×2500 = 1875 g

I hope this is helpful to you..........

Answer 2

Answer:

1 (I)=15 (ii)625(iii) 15 is the answer