Math, asked by radha2210, 1 year ago

1)What should be taken away from
3x^{2}  - 4y^{2}  + 5xy + 20
to obtain
 - x^{2}  - y^{2}  + 6xy + 20


Answers

Answered by Anonymous
1
3x2 − 4y2 + 5xy + 20) − p = − x2 − y2 + 6xy + 20

p = (3x2 − 4y2 + 5xy + 20) − (− x2 − y2 + 6xy + 20)

= 3x2 − 4y2 + 5xy + 20 + x2 + y2 − 6xy − 20

= 3x2 + x2 − 4y2 + y2 + 5xy − 6xy + 20 − 20

= 4x2 − 3y2 − xy


radha2210: is it 3y square what you have written in ur answer
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