Question

1. What will be the output of the following program?
#include<stdio.h>
int min(int x, int y) {
return (y <x)? y: x;
}
int main() {
int a[] = {-5, 9, 8,-8, -2};
int z = a[0], n=5, i=0,c=a[0];
for (i = 1;i<n; i++) {
c=min(a[i], c+a[i]);
z = min(z, c);
}
printf("%d", z);
}​

Answer 1

Answer:

-10

Explanation:

For i=1

c = min (9, 4) = 4

z = min (-5, 4) = -5

For i=2

c = min (8, 12) = 8

z = min (-5, 8) = -5

For i=3

c = min (-8, 0) = -8

z= min (-5, -8) = -8

For i=4

c= min(-2, -10) = -10

z = min (-8, -10) = -10

Hence answer = -10

Answer 2

-10 is the required output

Explanation:

#include<stdio.h>

int min(int x, int y) {

return (y <x)? y: x;

}

int main() {

int a[] = {-5, 9, 8,-8, -2};

int z = a[0], n=5, i=0,c=a[0];

for (i = 1;i<n; i++) {

c=min(a[i], c+a[i]);

z = min(z, c);

}

printf("%d", z);

}​

• -10 is the required output

hence, -10 is the correct answer.