Math, asked by suganthilogasenthil, 2 months ago

area of a rectangle is (3a^2+5ab+2b^2) one of its side is (a+b) what is the perimeter​

Answers

Answered by souvik2229
3

Step-by-step explanation:

breadth = 3a+2b

length= a+b

perimeter= 8a+6b

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Answered by mittalsapna19
6

Answer:

2 × (4a + 3b) = 8a + 6b

Step-by-step explanation:

Area of rectangle = L × B

Let the given side be the breadth of rectangle.

3a^2 + 5ab + 2b^2 = L × (a+b)

Factorising LHS,

3a^2+ 5ab+ 2b^2

3a^2+ 3ab + 2ab+2b^2

3a (a+ b) + 2b(a+ b)

(3a+ 2b) (a+ b)

(3a + 2b) (a +b) = L × (a+b)

(3a + 2b) (a +b) ÷ (a+b) = L

3a + 2b = Length

Perimeter = 2× (l + b)

= 2 × (3a + 2b + a + b).

= 2 × (4a + 3b)

= 8a + 6b

Answer ..

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