Question

1. When a dice is thrown twice find the probability of the sum of the numbers on the uppermost faces of the dice is
I). 4 or 5.
ii). more than 10.
iii). Less than 6.
iv). more than 12?
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Answer 1

Answer:

Less than 6.

Step-by-step explanation:

There are 6 possible results per die, so a total of 36 possible combinations.

There are 6 possible results per die, so a total of 36 possible combinations.Of these, the combinations which sum to 10 are easily counted: a 6 and a 4, a 4 and a 6, or two 5s; 3 such combinations.

There are 6 possible results per die, so a total of 36 possible combinations.Of these, the combinations which sum to 10 are easily counted: a 6 and a 4, a 4 and a 6, or two 5s; 3 such combinations.A probability is found by dividing outcomes that fit the requirements by the total possible outcomes, in this case, we have 3/36, or 1/12