Question

1. When the pressure of 5L of N, is doubled and its temperature is raised from 300K to 600K.thefind
volume of the gas would be
(A) 10 L
(B) 5L
(C) 15L
(D) 20 L​

Answer 1

Answer:

B) 5

Explanation:

Applying Ideal gas equation

$pv = nrt$

.•. let initial pressure be P and final pressure be 2P and unknown volume be V,

Let no. of moles be n

then,

$p \times 5 = nr \times 300$

now from gaining equation from final conditions,

$2p \times v = nr \times 600$

now dividing bothe the equations we get,

$\frac{5}{v} = 1$

$v = 5lit$