Question

1) Which term of a sequence 4, 7, 10, 15 --- is 37?
B) 12th term
C) 13thterm
D) 10thterm
A) 11th
term​

Answer 1

Correct Question :–

• Which term of a sequence 4, 7, 10, 13 --- is 37?

B) 12th term

C) 13thterm

D) 10thterm

A) 11th term

ANSWER :–

GIVEN :–

• Given series is 4 , 7 , 10 , 15 , .......... 37.

TO FIND :–

• Which term is 37 of given series = ?

SOLUTION :–

• We know that nth term of A.P. –

$\\ \large \: \longrightarrow \: { \boxed{ \sf T_{n} = a + (n - 1)d}}$

• Here –

$\\ \sf \: \: \: \: { \huge{.}} \: \: a = first \: \: term \: = 4$

$\\ \sf \: \: \: \: { \huge{.}} \: \: d = common \: \: difference \: = 3$

$\\ \sf \: \: \: \: { \huge{.}} \: \: T_{n} = n \th \: \: term \: = 37$

• So that –

$\\ \: \implies \: \sf 37 = 4+ (n - 1)3$

$\\ \: \implies \: \sf 37 = 4+ 3n - 3$

$\\ \: \implies \: \sf 37 = 3n + 1$

$\\ \ \: \implies \: \sf 3n = 36$

$\\ \: \implies \: \sf n = \cancel \dfrac{36}{3}$

$\\ \large \implies {\boxed{ \sf n = 12}}$

$\\ \sf { \huge{.}} 12 \th \: \: term \: \: of \: \: A.P. \: \: is \: \: 37$

• Hence Option (B) is correct .

Answer 2

✯✯ QUESTION ✯✯

1) Which term of a sequence 4, 7, 10, 13 --- is 37?

B) 12th term

C) 13th term

D) 10th term

A) 11th term

━━━━━━━━━━━━━━━━━━━━

✰✰ ANSWER ✰✰

$\implies\tt{4,7,10,13 .. is\:37?}$

➥Using : -

$\implies\tt{\large{\boxed{\bold{\bold{\purple{\sf{{T}_{n}=a+(n-1)d}}}}}}}$

➮Here : -

• First Term (a) = 4
• Common Difference (d) = 3
• ${T}_{n}$ (nth Term) = 37

➥Putting Values : -

$\implies\tt{37=4(n-1)3}$

$\implies\tt{37=4+3n-3}$

$\implies\tt{-3n=4-3-37}$

$\implies\tt{-3n=1-37}$

$\implies\tt{-3n=-36}$

$\implies\tt{n=\cancel\dfrac{-36}{-3}}$

$\green\longmapsto\:\large\underline{\boxed{\bf\blue{n}\orange{=}\red{12}}}$

☛So, Option B) 12th Term is Correct....