Question

1. Which value of resistance P shown in the
circuit will allow 1080 watts to be dissipated​

Answer 1

1. Question⇒   Which value of resistance P shown in the  circuit will allow 1080 watts to be dissipated​

Explanation:

• Answer is p=12.467 ohms
• steps followed
• 1) The Resistance "p" is removed.
• 2) The rest of the Circuit is reduced to its thevenin's equivalent, with voltage Vth=125V, this is calculated at the point where resistor was present previously and then Rth is found to be 2 ohms.
• 3) Equivalent circuit with Vth=125V and Rth=2 ohms is taken along with the resistor (R) and an expression for power P= V*I is equated to 1080watts  
• and the resistance is found from the expression.