Question

1/whole root 7-4root3

Answer 1

Hi ,

1 ) √( 7 - 4√3 )

= √ ( 7 - 2√4 × 3 )

= √ [ 4 + 3 - 2√ 4 × 3 )

= √ [ 2² + ( √3 )² - 2 × 2 × √3 ]

= √ ( 2 - √3 )1

= 2 - √3 ---( 1 )

Now ,

1/( √ 7 - 4√3 )

= 1/ ( 2 - √3 )

= ( 2 + √3 )/[( 2 - √3 ) ( 2 + √3 ) ]

= ( 2 + √3 ) / [ 2² - ( √3 )² ]

= ( 2 + √3 ) / ( 4 - 3 )

= 2 + √3

I hope this helps you.

: )