Question

1
Write a quadratic polynomial, sum of whose

zerdes is 2 and product is -8​

Answer 1

Answer:

• x² - 2x - 8 = 0

Step-by-step explanation:

Given that,

• Sum of roots (α + β) = 2
• Product of roots (αβ) = -8

As we know that,

⟹ Quadratic polynomial = x² - (α + β)x + αβ = 0

⟹ Quadratic polynomial = x² - (2)x + (-8) = 0

⟹ Quadratic polynomial = x² - 2x - 8 = 0.

Answer 2

Answer :-

• x² - 2x - 8

Given :-

• Sum and product of of zeroes is 2 and- 8.

To Find :-

• The quadratic polynomial.

Solution :-

Here

• sum of zeroes = 2
• product of zeroes = - 8

As we know that

Formula for finding quadratic polynomial is :-

x² - (sum of zeroes)x + product of zeroes

According to question :-

x² - (α + β)x + (α × β)

→ x² - ( 2)x + (- 8)

→ x² - 2x - 8

Hence, the required quadratic polynomial is x² - 2x - 8.