(1) Write the dimensional formal of inertia.
(2) check the correctness of formula v2-u2=2as.
(3) Derive the formula s=ut+1/2 at2.
(4) State triangle law of motion
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( 1). S I unit of inertia = kg m^2
So, Dimensional formula of inertia = [ M L^2 T °]
( 2). V^2 - U^2 = 2as
In LHS,
[ LT ^-1] ^2
= [ L^2 T ^-2]
In RHS,
= 2 a s
=[ LT^-2] [L]
= [ L^2 T ^ - 2]
Hence, LHS = RHS
So, Dimensional formula is correct.
(3) In attached picture.
( 4). In attached picture.
So, Dimensional formula of inertia = [ M L^2 T °]
( 2). V^2 - U^2 = 2as
In LHS,
[ LT ^-1] ^2
= [ L^2 T ^-2]
In RHS,
= 2 a s
=[ LT^-2] [L]
= [ L^2 T ^ - 2]
Hence, LHS = RHS
So, Dimensional formula is correct.
(3) In attached picture.
( 4). In attached picture.
Attachments:
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