Question

[{(1/x)^-1}^-1]^-1 =​

Answer 1

Answer:

$([(\frac{1}{x} )^{-1}]^{-1})^{-1}$ $=x$

Step-by-step explanation:

$([(\frac{1}{x} )^{-1}]^{-1})^{-1}$

$=([(\frac{1}{\frac{1}{x}} )]^{-1})^{-1}$  [∵ $a^{-n} = \frac{1}{a^n}$]

$=([(x )]^{-1})^{-1}$

$=(\frac{1}{x} )^{-1}$  [∵ $a^{-n} = \frac{1}{a^n}$]

$=(\frac{1}{\frac{1}{x}} )$ [∵ $a^{-n} = \frac{1}{a^n}$]

$=x$