Question

1/x+1 - 1/x-1 = 3 where x is not equal to +1 or -1​

Answer 1

Answer:

Step-by-step explanation:

Hi mate hope it helps...

Answer 2

Question :-

$\frac{1}{x + 1} - \frac{1}{x - 1} = 3$

where x is not equal to ±1 .

$\huge{\mathfrak{\underline{\red{Solution!}}}}$

$=> \frac{1}{(x + 1)} - \frac{1}{(x - 1)} = 3$

$=> \frac{x - 1 -( x + 1)}{(x - 1)(x + 1)} = 3$

$=> \frac{x - 1 -x - 1}{(x - 1)(x + 1)} = 3$

$=> \frac{- 1 - 1}{(x - 1)(x + 1)} = 3$

$=> - 2 = 3(x - 1)(x + 1)$

$=> (x - 1)(x + 1) = \frac{ - 2}{3}$

Here, we will get two conditions and two answers...

First one,

$= > \: x - 1 = \frac{ - 2}{3}$

$= > \: x = \frac{ - 2}{3} + 1$

$= > \: x = \frac{ - 2 + 3}{3}$

$= > \: x = \frac{1}{3} \: ans.$

Second one,

$= > \: x + 1 = \frac{ - 2}{3}$

$= > \: x = \frac{ - 2}{3} - 1$

$= > \: x = \frac{ - 2 - 3}{3}$

$= > \: x = \frac{ - 5}{3} \: ans.$

Hope It Helps♡