Question

(1/x-1)+(1/y-2)=3 and (2/x-1)+(3/y-2)=5 solve by elimination method of linear simultaneous equation ​

Answer 1

Answer:

x=5/4 and y=1

Step-by-step explanation:

let (1/x-1)+(1/y-2)=3. .....1

and (2/x-1)+(3/y-2)=5. ....2

now 1+2

(3/x-1)+(4/y-2)=8. ....3

now 2-1

(1/x-1)+(2/y-2)=2. ....4

now 3-4

(2/x-1)+(2/y-2)=6

form equetion2

6+(1/y-2)=5

1/y-2=-1

1=-y+2

then y=1

now put the value of y in equetion 1

(1/x-1)+(1/1-2)=3

(1/x-1)-1=3

1/x-1=4

1=4x-4

4x=5

then x=5/4