Math, asked by Gagan1381, 8 months ago

1/(x-1)(x-2)+1/(x-2)(x-3)=2/3 solvex

Answers

Answered by shravansangeeth007
1

Answer:

x=0 or x=4

Step-by-step explanation:

1/(x-1)(x-2)+1/(x-2)(x-3)=2/3 => (x-3+x-1)/(x-1)(x-2)(x-3)=2/3

=>(2x-4)/(x-1)(x-2)(x-3)=2/3 => 2(x-2)/(x-1)(x-2)(x-3)=2/3

2/(x-1)(x-3)=2/3=> 6=2(x-1)(x-3)

=> 6=2(x^2-4x+3) => 6= 2x^2-8x+6

=> 2x^2-8x=0 => x(2x-8)=0

=> x=0 or 2x-8=0

=> x=0 or 2x=8

=> x=0 or x=4

Answered by abhisheksuresh2006
0
X=0 or X= 4..............
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