Question

1/ (x-1) (x-2) + 1/(x-3) (x-2) = 2/3​

Answer 1

Answer:

x=0 , x=4

Step-by-step explanation:

1/ (x-1) (x-2) + 1/(x-3) (x-2) = 2/3

taking LCM

(x-3)+(x-1)/(x-1)(x-2)(x-3)=2/3

2x-4/(x-1)(x-2)(x-3)=2/3

taking 2 as common

2(x-2)/(x-1)(x-2)(x-3)=2/3

2 in lhs and 2 in rhs get cancel

so

(x-2)/(x-1)(x-2)(x-3)=1/3

x-2 get cancel in numerator and denominator

so

1/(x-1)(x-3)=1/3

3=(x-1)(x-3)

3=xsquare -3x-x+3

3=xsquare-4x+3

xsquare-4x=0

taking x common

x(x-4)=0

x=0,4