Math, asked by Garvit0706, 10 months ago

1/(x-1)(x-3)+1/(x-2)(x-3)=2/3

Answers

Answered by AJAYMAHICH
0

Step-by-step explanation:

1/(x-3)(x-1)+1/(x-2)(x-3)=2/3

3/(x-1) + 3/(x-2) = 2(x-3)

3x-6+3x-3 = 2(x-1)(x-2)(x-3)

6x-9 = 2(x^2-3x+2)(x-3)

6x-9 = 2(x^3 - 3x^2 + 2x - 3x^2 + 9x - 6 )

6x-9 = 2x^3 - 12x^2 + 22x - 12

2x^3 - 12x^2 + 16x - 3 = 0

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