Question

1/x-1/x+b=1/a-1/a+b
solve this.. fast..
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Answer 1

Answer:

here is your ans...hope you will understand

Answer 2

Answer:

$\frac{1}{x} - \frac{1}{x + b} = \frac{1}{a} - \frac{1}{a + b} \\ taking \: lcm \\ \frac{x + b - x}{(x)(x + b)} = \frac{a + b - a}{(a)(a + b)} \\ \frac{b}{ {x}^{2} + bx} = \frac{b}{ {a}^{2} + ab} \\ cross \: multiplying \: after \: cancelling \: b \\ equation \: becomes \\ {a}^{2} + ab = {x}^{2} + bx \\ { a }^{2} - {x}^{2} = bx - ab \\ (a + x)(a - x )= b(x - a) \\ which \: can \: be \: written \: as \\ (a + x)(a - x )= - b( a - x) \\ cancelling \: ( a- x) \\ x = - ( a+ b)$

Here is the answer...

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