Question

1/x+2+1/x=3/4 solve the question

Answer 1

$\large{solving</p><p>[tex] \frac{1}{x } + \frac{2}{1} + \frac{1}{x } = \frac{3}{4}$

}[/tex]

$\frac{x +2 {x + x}^{2} }{ {x}^{2} } = \frac{3}{4}$

$3 {x = 4 {x}^{2} }^{} + 8x + 4x$

$4 {x}^{2} + 9x = 0$

$x(4x + 9) = 0$

$x = 0$

$4x + 9 = 0$

$x = \frac{ - 9}{4}$

$\large{thevalueofXis}$

$x = 0or \: x = \frac{ - 9}{4}$

Answer 2

SOLVING EQUATION IN ONE VARIABLE :-

$\frac{1}{x + 2} + \frac{1}{x} = \frac{3}{4} \\ \\ \\ \implies \frac{x + x + 2}{x(x + 2)} = \frac{3}{4} \\ \\ \\ \implies \frac{2x + 2}{ {x}^{2} + 2x } = \frac{3}{4} \\ \\ \\ \implies \frac{8x + 8}{ {x}^{2} + 2x} = {3} \\ \\ \\ \implies 3 {x}^{2} + 6x - 8x - 8 = 0 \\ \\ \\ \implies 3{x}^{2} - 2x - 8 = 0 \\ \\ \\ \implies 3 {x}^{2} - 6x + 4x - 8 = 0 \\ \\ \\ \implies 3x(x - 2) + 4(x - 2) = 0 \\ \\ \\ \\ \implies (x - 2)(3x + 4) = 0 \\ \\ \\ \implies \boxed{x = 2 \: \: or \: \: x = \frac{ - 4}{3} }$

[ANS]