Question

1^x=2.
Find no of solutions to the equation?​

Answer 1

0

Given equation can be written as

tan

−1

(x−1)+tan

−1

(x+1)=tan

−1

3x−tan

−1

x

⇒tan

−1

1−(x−1)(x+1)

x−1+x+1

=tan

−1

1+3x

2

3x−x

⇒

2−x

2

2x

=

1+3x

2

2x

⇒x+3x

3

=2x−x

3

⇒4x

3

−x=0

⇒x=0,x=±1/2

none of which satisfies 1<x<

2

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