Question

A car is starting its motion from the rest condition with an

acceleration of 3 m/s². Find the speed of the car after 10

sec in km/h and distance travelled during 10 sec.​

Answer 1

ans.:-

Spead of car after 10 sec.

v = u + at

= 0 + 3× 10

= 30 m/sec.

= 30× 3600/1000 km/hr.

= 10.8 km/h

distance travelled during 10 sec.

s = ut + 1/2 at^2

= 0 × 10 + 1/2 × 3 × 10^2

= 1/2 × 300

= 150 m

= 150 × 0.001 hr.

= 0.150 hr.

Answer 2

Answer:

speed=108km/h

distance =150m

Explanation:

(1) speed =v=u+at ( first equation)

=0=0+(3)(10)

=0+30

=30m/s^

=30×18/5

=6×18

=108 km/ h

(2) distance = s= ut+1/2at^

s=(0×10)+1/2(3)(10)^

s=0+1/2(3)(100)

s= 0+1/2(300)

s=0+150

s=150m