A car is starting its motion from the rest condition with an
acceleration of 3 m/s². Find the speed of the car after 10
sec in km/h and distance travelled during 10 sec.
Answers
ans.:-
Spead of car after 10 sec.
v = u + at
= 0 + 3× 10
= 30 m/sec.
= 30× 3600/1000 km/hr.
= 10.8 km/h
distance travelled during 10 sec.
s = ut + 1/2 at^2
= 0 × 10 + 1/2 × 3 × 10^2
= 1/2 × 300
= 150 m
= 150 × 0.001 hr.
= 0.150 hr.
Answer:
speed=108km/h
distance =150m
Explanation:
(1) speed =v=u+at ( first equation)
=0=0+(3)(10)
=0+30
=30m/s^
=30×18/5
=6×18
=108 km/ h
(2) distance = s= ut+1/2at^
s=(0×10)+1/2(3)(10)^
s=0+1/2(3)(100)
s= 0+1/2(300)
s=0+150
s=150m