Math, asked by sauravkr85213760, 3 months ago

1-(x-2)-[(x-3)-(x-1)]=0​

Answers

Answered by shreyapoojary995
0

Answer:

1-(x-2)-(x-3)-(x-1)=0

1-x+2-x+3-x+1=0

7-3x=0

3x=7

x=7/3

Answered by academymunnas
0

Answer:

x-2-(x-3-(x-1))-0

Step 1: Simplify both sides of the equation.

x-2--1(x-3-(x-1))-0(Distribute the Negative

x-2-(x-3-(x-1))-0

x+-2+-1x+(-1)(-3)+-1(-x)+(-1)(1)-0

x+2+x+3+x+-1=0 (x+-x+x)+(-2+3+-1)-0(Combine Like Terms) x=0

x=0

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