(1-x)/3 - 3/2[ 2-(x-5)/2] + (x+3)/4 = 1
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2(
x+3
2x−1
)−3(
2x−1
x+3
)=5
⇒ (
x+3
4x−2
)−(
2x−1
3x+9
)=5
(4x−2)(2x−1)−(3x+9)(x+3)=5(x+3)(2x−1)
(8x
2
−4x−4x+2)−(3x
2
+9x+9x+27)=5(2x
2
−x+6x−3)
8x
2
−8x+2−3x
2
−18x−27=10x
2
+25x−15
5x
2
−26x−25=10x
2
+25x−15
5x
2
+50x+x+10=0
5x(x+10)+1(x+10)=0
(5x+1)(x+10)=0
5x+1=0 or x+10=0
x=
5
−1
or x=−10
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