Math, asked by khyati4267, 1 year ago

1/x-a-1/a-b=1/b-1/a
kindly solve it as fast as possible
its very very urgent
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Answers

Answered by pankaj2977
0

search at Google for this answer jl

Answered by hananb
0

Answer:

1/(x-a) -1/(a-b) = 1/b - 1/a

=> 1/(x-a) = 1/(a-b) + 1/b - 1/a

=> 1/(x-a) = 1/(a-b) + (a-b)/ab

=> 1/(x-a)

= (ab + a^2 + b^2 + 2ab) /ab(a-b)

=> (x-a)

= ab(a-b)/(a^2 + b^2 + 3ab)

=> x

= a + (ab(a-b)/(a^2 + b^2 + 3ab))

=> x

= (a^3 + a(b^2) + 3(a^2)b + (a^2)b -a(b^2))/(a^2 + b^2 + 3ab))

=> x

= (a^3 + 4(a^2)b)/(a^2 + b^2 + 3ab))

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