Question

1/(x-a)-1/(x-a+c)=1/(x-b-c)-1/(x-b) solve​

Answer 1

value of x = (a + b)/2

1/(x - a) - 1/(x - a + c) = 1/(x - b - c) - 1/(x - b)

⇒(x - a + c - x + a)/(x - a)(x - a + c) = (x - b - x + b + c)/(x - b - c)(x - b)

⇒c/(x - a)(x - a + c) = c/(x - b - c)(x - b)

⇒(x - b - c)(x - b) = (x - a)(x - a + c)

⇒(x - b)(x - b) - c(x - b) = (x - a)(x - a) + c(x - a)

⇒x² - 2bx + b² - cx + bc = x² - 2ax + a² + cx - ca

⇒2ax - 2bx - 2cx + b² + bc = a² - ca

⇒2x(a - b - c) = a² - ca - bc - b²

⇒2x(a - b - c) = (a - b)(a + b) - c(a + b)

⇒2x(a - b - c) = (a + b)(a - b - c)

⇒x = (a + b)(a - b - c)/2(a - b -c) = (a + b)/2

hence value of x = (a + b)/2

also read similar questions : To solve x+y=3 ; 3x-2y-4=0 by determinant method find D.

(A) 5

(B) 1

(C) -5

(D) -1

https://brainly.in/question/4328554

solve for x : 1/a+b+c =1/a+1/b+1/x

https://brainly.in/question/1118204

Answer 2

Answer:

Refer to this answer.

https://brainly.in/question/1118204