Math, asked by Kamrul12, 8 months ago

1/(x-a-b)=1/x -1/a -1/b solve this

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Answered by mukeshsinghrawat875
0

Answer:

Q-3. fill in the blanks si that following statements become true : i) 3+ _______= 0 ii). -2 +(-7)=(-7)+_______ iii)8+(-8)=_______ iv)-51+______=-51. v): 2+[(-7)+8] =(3+(____) ) vi). [3+(-8)] +______=3 +[(-8)+7]

Step-by-step explanation:

Q-3. fill in the blanks si that following statements become true : i) 3+ _______= 0 ii). -2 +(-7)=(-7)+_______ iii)8+(-8)=_______ iv)-51+______=-51. v): 2+[(-7)+8] =(3+(____) ) vi). [3+(-8)] +______=3 +[(-8)+7]Q-3. fill in the blanks si that following statements become true : i) 3+ _______= 0 ii). -2 +(-7)=(-7)+_______ iii)8+(-8)=_______ iv)-51+______=-51. v): 2+[(-7)+8] =(3+(____) ) vi). [3+(-8)] +______=3 +[(-8)+7]Q-3. fill in the blanks si that following statements become true : i) 3+ _______= 0 ii). -2 +(-7)=(-7)+_______ iii)8+(-8)=_______ iv)-51+______=-51. v): 2+[(-7)+8] =(3+(____) ) vi). [3+(-8)] +______=3 +[(-8)+7]Q-3. fill in the blanks si that following statements become true : i) 3+ _______= 0 ii). -2 +(-7)=(-7)+_______ iii)8+(-8)=_______ iv)-51+______=-51. v): 2+[(-7)+8] =(3+(____) ) vi). [3+(-8)] +______=3 +[(-8)+7]Q-3. fill in the blanks si that following statements become true : i) 3+ _______= 0 ii). -2 +(-7)=(-7)+_______ iii)8+(-8)=_______ iv)-51+______=-51. v): 2+[(-7)+8] =(3+(____) ) vi). [3+(-8)] +______=3 +[(-8)+7]

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