1 ) (x+a) (x+b) =
2 ) ½[(a+b)²+(a-b)²] =
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Ans 1 : ( x + a ) ( x + b )
x² + xb + ax + b²
Ans 2 : ½ { ( a + b )² + ( a + b )² }
½ ( a² + ab + ab + b² ) + ( a² + ab + ab + b² )
½ × 2a² + 4ab + 2b²
a² + 4ab + 2b²
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1 ) (x+a) (x+b) = (x)² + (a + b)×X + a(b)
2 ) ½[(a+b)²+(a-b)²] = ( a² + b² )
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