1+ x log x
(a) Evaluate
dx.
Answers
Answered by
0
Hi !
Solution :-
We have to differentiate the function .
dy/dx = 1+ xlogx
dy/dx of xlogx is 1+ logx (by product rule ) so,
=> 0 + x* 1/x + 1* logx
=> 1 + logx is Answer
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Hope it helps you !
@Raj ❤
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