Math, asked by anishpal94, 4 months ago

1. x+x+1=0 সমীকরণটির বীজগুলির বর্গ যে সমীকরণের বীজ, সেই সমীকরণটি নির্ণয় করি​

Answers

Answered by heymickeyyy777
0

Answer:

-3 is the answer

Step-by-step explanation:

as we can see we have to add both the x and the product will be 2x and after after that we have to take one from this I to the another side then we have to make a - 2 = 2 - 2 x = 2 - 1 and answer is -3 please mark as the brainliest

Answered by silverstonfree519
0

Answer:

i)25−4x

2

−12xy−9y

2

=25−(4x

2

+12xy+9y

2

)

=5

2

−((2x)

2

+2×2x×3y+(3y)

2

)

=5

2

−(2x+3y)

2

=(5+2x+3y)(5−(2x+3y))

=(5+2x+3y)(5−2x−3y)

ii)x

2

−a

2

+10ab−25b

2

=x

2

−(a

2

−10ab+25b

2

)

=x

2

−(a

2

−2×a×5b+(5b)

2

)

=x

2

−(a−5b)

2

=(x+a−5b)(x−(a−5b))

=(x+a−5b)(x−a+5b)

iii)6xy+x

2

+9y

2

−4a

2

=(2×x×3y+x

2

+(3y)

2

)−(2a)

2

=(x+3y)

2

−(2a)

2

=(x+3y+2a)(x+3y−2a)

iv)9x

2

+4+12x−a

2

+2ab−b

2

=((3x)

2

+(2

2

)+2×3x×2)−(a

2

−2ab+b

2

)

=(3x+2)

2

−(a−b)

2

=(3x+2+a−b)(3x+2−(a−b))

=(3x+2+a−b)(3x+2−a+b)

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