(1/x) +x=4, form the general form of quadratic equation?
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For the general form of quadratic equation, we can write it as————
ax^2 + bx+c =0 [ where, a, b and c are constants]
If you want to find the roots, - - - - - - -
4a^2x^2+4abx +4ac =0 [ by multiplying both sides with 4a]
Or, (2ax+b)^2 = b^2 - 4 ac
Or, (2ax+b)= +/- sqrt (b^2–4ac)
Or, a =[ - b +/- sqrt (b^2–4ac)]/2
So, a= [-b +sqrt (b^2–4ac)]/2, or, a =[-b - sqrt (b^2–4ac)]/2………
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