Question

1+x+x2/1-x+x2=62(1+x)/63(1-x)​

Answer 1

Answer:

here you go

Step-by-step explanation:

(1+x+x²)/(1-x+x²) = 62(1+x)/63(1-x)

⇒63(1-x)(1+x+x²) = 62(1+x)(1-x+x²)

⇒63[1+x+x²-x-x²-x³] =62 [ 1-x+x² +x-x²+x³]

⇒63[1-x³]= 62[1+x³]

⇒63-63x³ =62 +62x³

⇒63-62 =62x³+63x³

⇒1= 125 x³

125x³ =1

x³ =1/125

x³ =(1/5)³

∴x=1/5