Question

(1/x+y/3)^3 expand the following​

Answer 1

Answer:

1/x^3 + y^3/9 + y/x^2 + y^2/3x

Answer 2

hey mate here's your answer! ;-

= (1/x)³ + (y/3)³ + 3(1/X)²(y/3) + 3(1/x)(y/3)²                  

∵(a+b)³ = a³+b³+3a²b+3ab²

1/x³+y³/27 + 3(1/x²)(y/3) + 3(1/x)(y²/9)

1/x³+y³/27 + (3* y/x² * 3) + (3* y²/x * 9)    canceling 3

1/x³+y³/27 + y/x² +  y²/x * 3 

1/x³+y³/27 + y/x² +  y²/3x 

Hope it helps you

have a good day :)