-1/x + y
x + y
tan
3.
xy <1=
1 - xy
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0
Answer:
Step-by-step explanation:
The given differential equation can be written as
dy
dx
=xy(x
2
siny
2
+1)⇒
x
3
1
dy
dx
−
x
2
1
y=ysiny
2
This equation is reducible to linear equation.
So putting v=−
x
2
1
∴
dy
dv
+2vy=2ysiny
2
The integrating factor of this equation is e
y
2
So the required equation is
ve
y
2
=∫2ysiny
2
e
y
2
dy+c=−
2
1
e
y
2
(siny
2
−cosy
2
)+c
⇒2v=(siny
2
−cosy
2
)+e
−y
2
⇒2=x
2
(cosy
2
−siny
2
−2ce
−y
2
)
hope it helps u
brainliest me
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