Question

1 - x² + 2 xy - y² do this factorization​

Answer 1

Step-by-step explanation:

The factor of 1−x

2

−2xy−y

2

is

Rearranging the terms

⇒ 1−(x

2

+2xy+y

2

)

⇒ −1(x+y)

2

[∵ (x+y)

2

=x

2

+2xy+y

2

]

⇒ (1−(x+y)

2

)

⇒ (1)

2

=(x+y)

2

[∵(1)

2

=1]

Using a

2

−b

2

=(a+b)(a−b)

⇒ (1−(x+y))(1+(x+y))

⇒ (1−x−y)(1+x+y) - solution

Answer 2

Answer:

$hey \: mate \: here's \: ur \: answer \\ 1-x² + 2 x y -y^{2} \\ = 1- (x² - 2xy + {y}^{2} ) \\ using \: identity \\ (a-b)^{2} = {a}^{2} - 2ab + {b}^{2} \\ = 1 - (x - {y}^{2} ) \\ = {1}^{2} - (x-y)^{2} \\ using \: identity \\ a²- {b}^{2} = (a-b)(a+b) \\ = [ 1 - (x-y)] [1 + (x-y)] \\ (1-x + y) (1 + x - y)$

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