Question

1) x²+3x²y+3xy²+2y³
2)1+9x+27x²+28x²
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Answer 1

Answer:

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Answer 2

Answer:

1) x² + 3x²y + 3xy² + 2y³

= x² + 3x²y + 3xy² + y² + y³

= (x + y)³ + y³

= {(x + y) + y} {x+y)² - (x + y)y + (y)²}

= (x + 2y) (x² + 2xy + y² - xy - y² + y²)

= (x + 2y)(x² +xy + y²)

2) 1 + 9x + 27x² + 28x³

= (1 +9x+ 27x² +27x³) + x³ =(1 + 3x)³ + (x)³

= {(1 + 3x) +x} {(1 + 3x)²- (1 + 3x).x + (x)²}

= (1 + 4x) (1 + 6x + 9x² - x- 3x² +x²)

= (1 + 4x ) (1 + 5x + 7x²)