Question

1 year ago a man was 7 times as old as his son. Now his age is equal to the square of his son's age. The present age of man's age is

Answer 1

let present age of son = x

hence present age of man = x^2

one year ago

x^2 - 1= 7(x-1)

x^2 -7x +6=0

x = 1 or 6

the value which satisfies the condition in the question is 6

hence boy is 6 and man is 36 years old in present time