Question

1 year ago A man was 8 times as old as his son at present his age is equal to the square of his son's age in years find their present age

Answer 1

his present age will be 49 years

Answer 2

Let the present age of son be x

So age of father=x^2

1 year ago their ages are x-1 and x^2-1 respectively

By the condition given in your question

x^2-1=8 (x-1)

x^2-1=8x-8

x^2-8x+7=0

x^2-x-7x+7=0

x (x-1)-7 (x-1)=0

(x-1)(x-7)=0

x=1. or. x=7

x=1 is not possible

So present age of son is 7 years

and age of father is 49 years