Question

1 year ago, a man was aged 8 times as old as his son.Now his age is equal to the square of his son's age.Find their present ages.

Answer 1

Let the age of the son one year ago be x years.

Age of the father one year ago = 8x years.

Present age of the father = 8x+1

Present age of the son = x+1

Given that (8x+1) = (x+1)2

(8x+1) = (x2 + 2x + 1)

x2 - 6x = 0

x(x - 6) = 0

x = 0 or x = 6

Son's age cannot be zero.

So, the present age of son is (x+1) i.e. 7 years.     ANS

Present age of the father = (8x+1) i.e. 49 years.  ANS