Question

10^10 electrons pass through the cross section of a conductor in 10^(-4) second. Find the current.

Answer 1

Answer:   1.62 ×10∧-5 Amperes

Explanation:1 electron contains 1.62×10∧-19 Coulumbs of charge

therefore 10∧10 electrons have 1.62×10∧-9 Coulumbs of charge

I=q/t

current=charge/time

current= (1.62×10∧-9) / 10∧-4

answer is 1.62×10∧-5 amperes