Question

10-√11/10+√11 rationalise​

Answer 1

Answer:

111 - 20√11 / 89

Explanation:

To rationalise a number, we need to multiply the inverse operation of the denominator with the numerator and the denominator too.

i.e. 10-√11/10+√11 × 10-√11/10-√11

=> (10-√11)^2 / (10+√11)*(10-√11)

Since, (a - b)^2 = a^2 - 2ab + b^2

And, (a + b) * (a - b) = a^2 - b^2

=> (10)^2 - 2*10*√11 + (√11)^2 / (10)^2 - (√11)^2

When we do squaring in a root number, then the 'root' and 'square' are cancelled.

=> 100 - 20√11 + 11 / 100 - 11

=> 111 - 20√11 / 89

Hope it helps u !!!!!!!

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