Question

10 ਦੇ ਦੋ ਲਗਾਤਾਰ ਗੁਣਜਾਂ ਦਾ ਗੁਣਨਫਲ 1200 ਹੈ। ਤਾਂ ਇਹਨ੍ਹਾਂ ਗੁਣਜਾਂ ਦਾ ਮੁੱਲ ਪਤਾ ਕਰੋ। The product of two successive multiples of 10 is 1200. Then find these multiples:10 के 2 लगातार गुणजों का गुणनफल 1200 है, तो गुणजों का मूल्य पता करें. *
20, 30
48, 25
60, 20
30, 40

Answer 1

HELLO DEAR,

GIVEN:- The product of two successive multiples of 10 is 1200. Then find these multiples:

SOLUTION- Let the first multiple of 10 is x.

And its successive multiple of x is (x+10).

Then as per question ,

x × ( x+ 10) = 1200

x^2 + 10x = 1200

x^2 + 10x - 1200 = 0

x^2 + 40x - 30x - 1200 = 0

x ( x + 40 ) -30 ( x + 40) = 0

(x - 30) ( x + 40 ) = 0

x = 30 , x = -40.

Therefore ,

X= 30 & - 40

if,x= 30 , then numbers are 30,40

if x = -40 , then numbers are-40,-30

I HOPE IT'S HELP YOU DEAR,

THANKS

Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

The product of two successive multiples of 10 is 1200

Then the multiples are

(a) 20, 30

(b) 48, 25

(c) 60, 20

(d) 30, 40

EVALUATION

Here it is given that The product of two successive multiples of 10 is 1200

Let us assume that the multiples are 10x and 10x + 10

So by the given condition

$\sf{10x(10x + 10) = 1200 \: }$

$\implies \sf{100x(x + 1) = 1200 \: }$

$\implies \sf{x(x + 1) = 12 \: }$

$\implies \sf{ {x}^{2} + x - 12 = 0 \: }$

$\implies \sf{ {x}^{2} + 4x - 3x - 12 = 0 \: }$

$\implies \sf{ x(x + 4) - 3(x + 4) = 0 \: }$

$\implies \sf{ (x + 4) (x - 3) = 0 \: }$

Which gives either x + 4 = 0 or x - 3 = 0

x + 4 = gives x = - 4

In this case the multiples are - 40 & - 30

Again x - 3 = 0 gives x = 3

In this case the multiples are 30 and 40

FINAL ANSWER

The product of two successive multiples of 10 is 1200

Then the multiples are

(d) 30, 40

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