Question

10.2. If the sum of the zeroes of the quadratic polynomial 3r-kr 6 is 3 find the value of k
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Answer 1

Given Data :-

• P(x) = 3r² - kr - 6
• α+β = 3

To Find :

• value of k

Solution :-

$\huge \tt α + β = - \frac{b}{a}$

then ,

$\huge \tt 3 = \frac{ \cancel- ( \cancel - k)}{3}$

$\huge \tt k = 3 \times 3 = 9$

$\large \tt \ast \: \: the \: \: value \: \: of \: \: k = 9$