Write2log3+3log5-log2 as a single logarithm
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0
Answer:
log(9*125/2)
Step-by-step explanation:
log 9 + log 125- log 2
log 9*125/2
Answered by
2
2log3+3log5-log2
2log3 = log9
3log5 = log125
Now,
log9 + log125 - log2
loga + logb = log a.b
log9 + log125 = x
x - log2
log9 + log125 = log1125
log1125 - log2
loga - logb = loga/b
log(1125/2)
log(562.5)
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