Question

10^24 molecules of gas collides normally on 5cm^2 area of surface at the rate of 10^20 molecules per second. the mass of the molecule is 3×10^-27 kg. find the pressure surface experienced by the surface assuming that the collision is elastic. average velocity of the molecule is 10^5 m/s.​

Answer 1

Explanation:

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Answer 2

ANSWER :

1.2×10² N/m²

EXPLANATION :

No. Of molecules of gas

which collide on surface area per sec (n) = 10^20

Area of surface =5 cm ²

Mass of each molecule =3×10^–27 kg

Avg. Velocity of molecules =10^5 m/s

Momentum = MV –(–MV)

=2MV

=2×m×n×v ... [M(total) =n×m]

=2×3×10^-27×10^20×10^5

=6×10¯²

Pressure =momentum

Area

= 6×10¯²÷5×10¯⁴

=1.2×10² N/m²