10^24 molecules of gas collides normally on 5cm^2 area of surface at the rate of 10^20 molecules per second. the mass of the molecule is 3×10^-27 kg. find the pressure surface experienced by the surface assuming that the collision is elastic. average velocity of the molecule is 10^5 m/s.
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ANSWER :
1.2×10² N/m²
EXPLANATION :
No. Of molecules of gas
which collide on surface area per sec (n) = 10^20
Area of surface =5 cm ²
Mass of each molecule =3×10^–27 kg
Avg. Velocity of molecules =10^5 m/s
Momentum = MV –(–MV)
=2MV
=2×m×n×v ... [M(total) =n×m]
=2×3×10^-27×10^20×10^5
=6×10¯²
Pressure =momentum
Area
= 6×10¯²÷5×10¯⁴
=1.2×10² N/m²
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