Question

10^2y = 25 then 10^-y​

Answer 1

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Given :

If $10^{2y} = 25$,

Then find the value of :

$10^{-y}$

Solution :

We know that ,

If $a^x = b$

Then, $a^{-x} = \frac{1}{b}$.

Also,

If $a^{2x} = b$

Then, $a^{x} =\sqrt{x}$.

Hence,

If $10^{2y} = 25$,

⇒ $10^y = \sqrt{25} = 5$

⇒ $10^{-y} = \frac{1}{5}$