(-10)³+(7)³+(3)³ ,Without actual calculating the cubes, find the value of it.
Answers
Answered by
80
Solution :
************************************
We know that ,
If x + y + z = 0 , then
x³ + y³ + z³ = 3xyz
**********************************
Here,
x = (-10 ) , y = 7 , z = 3 ,
Now ,
x + y + z
= -10 + 7 + 3
= 0
Therefore ,
( -10 )³ + 7³ + 3³
= 3xyz
= 3× ( -10 ) × 7 × 3
= - 630
Therefore ,
The value of ( -10 )³ + 7³ + 3³
= - 630
•••••
************************************
We know that ,
If x + y + z = 0 , then
x³ + y³ + z³ = 3xyz
**********************************
Here,
x = (-10 ) , y = 7 , z = 3 ,
Now ,
x + y + z
= -10 + 7 + 3
= 0
Therefore ,
( -10 )³ + 7³ + 3³
= 3xyz
= 3× ( -10 ) × 7 × 3
= - 630
Therefore ,
The value of ( -10 )³ + 7³ + 3³
= - 630
•••••
Answered by
39
- 10 + 7 + 3 = 0
so,
x³ + y³ + z³ -3xyz
(-10)³+(7)³+(3)³ = 3(-10)(7)(3)
-1000 + 49 + 9 = -630
-630 = -630
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