Question

(28)³+(-15)³+(-13)³,Without actual calculating the cubes, find the value of it.

Answer 1

Heya......!!!

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We have to find the value :

=>  (28)³ + (–15)³ + (-13)³


Let -» a = 28

b -» -15

c -» -13


=> a + b + c = 0

If -» a + b + c = 0. Then a³ + b³ + c³ = 3abc



→ 28)³+ (–15)³ + (-13)³ = 3(28)(-15)(-13) = 16380


→ (28)³+ (–15)³ + (-13)³ = 16380


Answer = 16380




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Hope It Helps You. ☺

Answer 2

Solution :

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We know that ,

If x + y + z = 0 , then

x³ + y³ + z³ = 3xyz

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Here ,

x = 28 , y = -15 , z = -13

Now ,

x + y + z

= 28 - 15 - 13

= 0

( 28 )³ + ( -15 )³ + ( -13 )³

= 3xyz

= 3 × ( 28 ) × ( -15 ) × ( -13 )

= 16380

( 28 )³ + ( -15 )³ + ( -13 )³ = 16380

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