10/3 of 1/2+2÷[2×[2-(2-1/5)}]
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Answer:
10/3×1/2+2÷[2×{2-(2-1/5)}]
=10/3×1/2+2÷[2×{2-1/5}]
=10/3×1/2+2÷[2×1/5]
=10/3×1/2+2÷2/5
=5/3+2÷2/5
=5/3+(1/2×2/5)
=5/3+2/10
=5/3+5/1
=10
Step-by-step explanation:
this is a form of bodmas
B=bracket
O=of mean multiple
D=Divide
M=multiply
A=Additional
S=Substrate
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