10(3x-4÷x)^2-3(3x-4÷x)-7
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Let, (3x-4÷x) = A
now,
10 A^2 - 3A - 7
= 10 A^2 - (10-7)A - 7
= 10 A^2 -10 A + 7A - 7
= 10A (A-1) + 7 (A-1)
= (A-1) (10A+7)
= (3x-4÷x -1) {10 (3x-4÷x) +7}
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