(10.5)^2 find the product of this using suitable Identity
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By using 1st identity
(x+y)^2
(x+y) (x+y)
x^2+2xy+y^2
10.5 can distribute= 10+0.5
Then
(10+0.5)^2
(10+0.5) (10+0.5)
(10)^2+2*10*0.5+(0.5)^2
100+10+0.25
110.25
Hope it will help you!
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